Balmerserien

                   ...hvad var spørgsmålet?

                  ...hvilke tanker har du gjort dig?

OK som førstegangsbruger
får du

                             Balmerserien er lyskvanter ved elektronspring fra m>2 til n=2

                             De tilhørende bølgelængder beregnes af Rydberg-formlen

                                        1/λ = (1,09737·10⁷ m^-1) • ((1/2²) - (1/m²))

hvoraf
                                         λ = (91,1267 nm) • ( 4m²/(m²-4) )
som for
                       m = 3
                          giver    
                                         λ_3→2 = (91,1267 nm) • ( 4•3²/(3²-4) ) = 710,788 nm

                       m = 4
                          giver    
                                         λ_4→2 = (91,1267 nm) • ( 4•4²/(4²-4) ) = 486,009 nm

                       m = 5
                          giver    
                                         λ_5→2 = (91,1267 nm) • ( 4•5²/(5²-4) ) = 433,937 nm

                       m = 6
                          giver    
                                         λ_6→2 = (91,1267 nm) • ( 4•6²/(6²-4) ) = 410,070 nm

med fotonenergi

                                          E_fot = (h•c) / λ = (1329,84 eV·nm) / λ

som for
                       m = 3
                          giver
                                          E_fot = (1329,84 eV·nm) / (710,788 nm) = 1,74 eV                      

                       m = 4
                          giver
                                          E_fot = (1329,84 eV·nm) / (486,009 nm) = 2,55 eV          

                       m = 5
                          giver
                                          E_fot = (1329,84 eV·nm) / (433,937 nm) = 2,86 eV

                       m = 6
                          giver
                                          E_fot = (1329,84 eV·nm) / (410,070 nm) = 3,02 eV