impuls

kraften F's impuls P = F*t 

1)

    vektorligning
                                             F = dp/dt = d(m·v)dt = dm/dt·v + m·dv/dt = m·dv/dt        da dm = 0

    størrelsesligning
    når F og v
    forudsættes ensrettede

                                             F = dp/dt = m·dv/dt       

                                             ∫ dp = F· ∫ dt           da F er konstant i de 2,6 s

                                             p = F·t

                                             p = (27 kN) · (2,6 s) = 70,2 kNs
 

2)
                                             ΔB = Δ(m·v) = m·Δv = p

3)

                                             m·Δv = p

                                             (104·10³ kg)·Δv = 70,2·10³ Ns = 70,2·10³ kg·m/s

                                             Δv = (70,2·10³ kg·m/s) / (104·10³ kg) = 0,675 m/s