Fysik Projekt

 3 c)
                                                d²x
                              m·g = m • -------
                                                dt²

                                      d²x
                              g = -------
                                      dt²

     hvoraf                            
                                       dx
                             v(t) = ----- = ∫ g dt = g•t + v_o
                                       dt


                             s(t) = x(t) = ∫(g•t + v_o) dt = (1/2)•g•t² + v_o•t + s_o

                             s(t) = (1/2)•g•t² + v_o•t + s_o

.

     med begyndelsesbetingelserne v_o og s_o

              

s er position, ikke?

   Jo

Okay tak :D

for
            v_o = s_o = 0

                                         opfylder
                                                              x(t) = (1/2)g•t²    differentialligning (5), da

                                                              dx/dt = g•t

                                                              d²x/dt² = g
                                        og dermed
                                                              m • (d²x/dt²) = m•g
 

okay :)

Kunne du måske også forklare opgave 3f?

se
 

det er da v(t), skal jeg ikke finde x(t)?