Kemi
hj haster formel
hej
der sttår i min opg at
in order to to make a calibration curve the following solutions are made
250 ml AL stock solution 10 mg AL / L prepared from ALCL3 6H2O
how many g of ALCL36H20 do you need to weight out
0,250 L = v
10 mg = n
m = n * M
M = ALCL3 6H2O = 447,8002
10 * 447,8002 = 4478,002 g
Svar #1
08. oktober 2009 af mathon
M(AlCl3*6H2O) = 241,46 g/mol hvoraf Al udgør 11,17%
10 mg Al ækvivalerer (10 mg)/0,1117 = 89,53 mg AlCl3*6H2O
Svar #3
08. oktober 2009 af msn88 (Slettet)
ok mange takk hvad med den her
c.
AL - standard solution transfer 10:00 mL AL stock solution to a 500 ml volumetric flask
fill the flask to the mark with water and mix
calculate the AL concentration in the standard solution expressed as mg/ L
0,500 * 0,1117 = 0,05585 mg( L
er det rigtig beregnet
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