Differentiere sammensat funktion

når h(x)=f(g(x)) gælder at

h'(x)=f '(g(x))* g'(x)

dvs. du skal finde den indre funktion g(x) og bruge ovenstående formel.

det har jeg gjort men ikke foået det rigtige resultat

c)

           f '(x) = 3 • (2 - √(x+1))² •  (0 - (1/(2•√(x+1)))  =  -(3/2)•(2 - √(x+1))² / √(x+1)

står der skal give det her men kan ikke selv komme til svaret

d)
                             3                                             -15(1-x²)⁴
       f '(x) =  ------------------ • 5•(1-x²)⁴ • (0-2x) = ---------------- = -15(1-x²)^4-(5/2) = -15(1-x²)^(3/2) =
                     2√((1-x²)⁵)                                       √((1-x²)⁵)

                                                                                                                                                                                                                                                            -15•√((1-x²)³)

tak

#3
 

c)

           f '(x) = 3 • (2 - √(x+1))² •  (0 - (1/(2•√(x+1)))  =  -(3/2)•(2 - √(x+1))² / √(x+1) =

                                 -3(2 - √(x+1))²     -3(((-1)(-2 + √(x+1))²)      -3(√(x+1) - 2)
                                -------------------- = ----------------------------  =  -------------------
                                      2√(x+1)                   2√(x+1)                       2√(x+1)